... 教學中會教各位如何使用java.util.List.* 的物件，此篇來解析java 容器中的List。 ... boolean, add(int index,E e), 將物件加入集合中指定的位置. ... <看更多>

List <String> newList = new LinkedList<>(listOne); newList.addAll(listTwo);. Prefer to use a LinkedList for efficient add operations. ArrayList ... ... <看更多>

Java provides a class called ArrayList that provides many useful methods for dealing with a collection of data ... ... <看更多>

This design decision appears mostly driven by naming. Name ArrayList suggests to reader a functionality similar to arrays - and it is natural for Java ... ... <看更多>